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	<title>Comments on: Great Circle algorithm</title>
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		<title>By: ER</title>
		<link>https://habitablezone.com/2023/04/14/great-circle-algorithm/#comment-51787</link>
		<dc:creator>ER</dc:creator>
		<pubDate>Sat, 15 Apr 2023 17:24:43 +0000</pubDate>
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		<description>What is the intercept and initial course from Los Angeles (34d 03&#039;N,  118d 15&#039;W) 
TO Manila (14d 35&#039;N, 120d 59&#039;E).


INPUT DATA
Ho = 90 degrees = 5400&#039;. 
DEC = 14d 35&#039;
GHA = 239d 01&#039;
Lat = 34d 03&#039;
Lon = -118d 15&#039;

INTERMEDIATE VALUES
&lt;strong&gt;LHA&lt;/strong&gt; = GHA + Lon = 239.01 + (-118d 15&#039;) = 120d 46&#039;
cos LHA = -.5115
cos DEC x cos LHA = &lt;strong&gt;C&lt;/strong&gt; = -.4951
sin DEC = &lt;strong&gt;S&lt;/strong&gt; =.2518
sin Lat = .5599
cos Lat = .8285

INTERCEPT CALCULATION
Hc = INVsin (( S x Sin Lat ) + ( C x Cos Lat ))
Hc = INVsin (-.2692)
Hc = -15d 37&#039; = -937&#039;
Intercept = Ho – Hc = 5400&#039; - (-937&#039;) = &lt;strong&gt; 6337 NM&lt;/strong&gt;



AZIMUTH CALCULATION
X = (( S x Cos Lat)  – (C x Sin Lat )) / cos Hc
X = ((.2086)-(-.2772))/cos Hc 
X = (.4858) /.9631
X = .5044
If X is greater than +1 or less than -1 (due to truncation error), just reset it to +1 or -1.

A = INVcos ( .5044 ) = 59d 43&#039;

If LHA &gt; 180 degrees, then Azimuth Z = A
Otherwise, Z = 360-A 
&lt;strong&gt;Z = 300d&lt;/strong&gt; since LHA &lt; 180d</description>
		<content:encoded><![CDATA[<p>What is the intercept and initial course from Los Angeles (34d 03&#8242;N,  118d 15&#8242;W)<br />
TO Manila (14d 35&#8242;N, 120d 59&#8242;E).</p>
<p>INPUT DATA<br />
Ho = 90 degrees = 5400&#8242;.<br />
DEC = 14d 35&#8242;<br />
GHA = 239d 01&#8242;<br />
Lat = 34d 03&#8242;<br />
Lon = -118d 15&#8242;</p>
<p>INTERMEDIATE VALUES<br />
<strong>LHA</strong> = GHA + Lon = 239.01 + (-118d 15&#8242;) = 120d 46&#8242;<br />
cos LHA = -.5115<br />
cos DEC x cos LHA = <strong>C</strong> = -.4951<br />
sin DEC = <strong>S</strong> =.2518<br />
sin Lat = .5599<br />
cos Lat = .8285</p>
<p>INTERCEPT CALCULATION<br />
Hc = INVsin (( S x Sin Lat ) + ( C x Cos Lat ))<br />
Hc = INVsin (-.2692)<br />
Hc = -15d 37&#8242; = -937&#8242;<br />
Intercept = Ho – Hc = 5400&#8242; &#8211; (-937&#8242;) = <strong> 6337 NM</strong></p>
<p>AZIMUTH CALCULATION<br />
X = (( S x Cos Lat)  – (C x Sin Lat )) / cos Hc<br />
X = ((.2086)-(-.2772))/cos Hc<br />
X = (.4858) /.9631<br />
X = .5044<br />
If X is greater than +1 or less than -1 (due to truncation error), just reset it to +1 or -1.</p>
<p>A = INVcos ( .5044 ) = 59d 43&#8242;</p>
<p>If LHA > 180 degrees, then Azimuth Z = A<br />
Otherwise, Z = 360-A<br />
<strong>Z = 300d</strong> since LHA < 180d</p>
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